Calculus Of One Real Variable – By Pheng Kim Ving
|
12.5 |
Return
To Contents
Go To Problems & Solutions
1. Distance Travelled And Displacement |
We're now going to find the distance travelled by and the
displacement of an object moving on a straight line given that
its velocity v = v(t) at any time t is known.
|
Fig. 1.1 Distance Travelled And Displacement. |
Let's distinguish between distance travelled and
displacement. Suppose the motion is along the x-axis. See Fig. 1.1. For
example:
Motion |
Distance Travelled |
Displacement |
If object moves from point 1 to point 3 |
2 |
2 |
If object moves from point 1 to point 3 then in reverse to point 2 |
3 |
1 |
If object moves from point 1 to point 3 then in reverse to point 1 |
4 |
0 |
If object moves from point 1 to point 3 then in reverse to point 0 |
5 |
–1 |
|
Note that distance travelled is a non-negative quantity
while displacement is a signed quantity. The object's displacement
is positive, respectively negative, if its final position is to the right,
respectively to the left, of its initial position. Displacement
may or may not be equal to distance travelled.
Distance Between 2 Points. Refer to Fig. 1.1. The
distance between point 1 and point 3 is 2. If the object travels from
point 1 to point 3, then its distance travelled is 2. If the object travels
from point 1 to point 3, reverses direction and
travels to point 2, and reverses direction and travels to point 3, then its distance
travelled is 2 + 1 + 1 = 4. The distance
between 2 points may or may not equal the total distance travelled by an object
between them. It equals the absolute
value of the displacement of the object between them.
Go To Problems & Solutions Return To Top Of Page
2. Finding Distance Travelled And Displacement |
Recall from Section
5.8 that speed is the absolute value of velocity, and that velocity is
positive, respectively negative, if
the object moves in the positive, respectively negative, direction. On the
normal x-axis, the
positive, respectively negative,
direction is left-to-right, respectively right-to-left.
|
Fig. 2.1
|
|
Fig. 2.2
Velocity v = k < 0,
where k is a constant.
|
|
Fig. 2.3
Motion Along x-Axis In Positive Direction With Variable Velocity.
|
|
Fig. 2.4
Distance Travelled = Displacement = Area
Of Colored Region.
|
|
Fig. 2.5
Motion Along x-Axis In Negative Direction With Variable Velocity.
|
|
Fig. 2.6
Distance Travelled = Area Of Colored
Region;
|
|
Fig. 2.7
Motion Along x-Axis In Positive And Negative Directions With Variable
|
|
Fig. 2.8
Distance Travelled = A1 + A2;
|
In summary:
|
Looking at Fig. 2.7 you may wonder what about x2 if we integrate from x1 to x3, as x2 lies outside
the interval [x1, x3],
so it appears that the motion from x2 to x3 is excluded. Well, we don't
integrate from x1 to x3, we integrate the velocity
v(t) from t1 to t3, and t2 lies inside the interval [t1, t3], as seen in
Figs. 2.7 and 2.8, so the velocity from t2 to t3 and thus
the motion from x2 to x3 are included.
a. The distance travelled by the object.
b. The displacement of the object.
Solution
a. Distance travelled:
b. Displacement:
EOS
Problems & Solutions |
a. The distance
travelled by the object.
b. The displacement of the
object.
Solution
a. v(0) = cos 0 = 1; so at time t = 0 sec the object travels in the positive direction with a speed of 1 m/sec.
Thus:
At time t = 3 sec, the object is back at where it was at time t = 0 sec.
a. The
distance travelled by the object.
b. The displacement of the
object.
a. Clearly:
from above calculation.
4. A body moves on the x-axis with acceleration a(t)
= d2x/dt2 = 6t
m/sec2. It starts at time t
= 0 with initial velocity
v0 = –3 m/sec.
a. Find the velocity v(t) as a function of t.
b. Find the total distance s travelled by the body from
time t = 0 sec
to time t = 4 sec.
c. Where is its position at
time t = 4 sec
relative to its position at time t
= 0 sec?
Solution
s = 56 m.
c. Displacement:
At time t = 4 sec, the position of the body is 52 m to the right of its position at time t = 0 sec.
v(t) = 2e–t
= 2/et
> 0 for all t,
so speed = |v(t)| = v(t) = 2/et;
speed decreases very rapidly toward 0 but is always > 0
as time passes.
Solution
The object moves 2 km throughout eternity.
Return To Top Of Page Return To Contents