## Calculus Of One Real Variable – By Pheng Kim Ving Chapter 13: Plane Curves – Section 13.1.1: Parametric Curves

13.1.1
Parametric Curves

 1. Parametric Curves

In Section 6.1.6 Part 2 we discussed the equations of the trajectory of the projectile motion. The graph of the trajectory is
re-produced here in Fig. 1.1. # The arrow head indicates the direction of motion.

First we found the set of 2 equations where t is the independent variable: The 1st 2 equations are of the form x = f(t), y = g(t), where f and g are continuous functions. We saw that these equations
are called parametric equations, t is called the parameter, and t is non-negative. In Example 3.1 of the same section we
learned that t has a maximum value denoted by tmax. So the common domain of f and g is I = set of all real numbers between
0 and tmax inclusive. Here the parameter t is time. The last equation is of the form y = F(x). It's a Cartesian equation. It was
obtained from the parametric equations by eliminating t. The graph of y = F(x) shown in Fig. 1.1 is the graph of the
corresponding parametric equations x = f(t), y = g(t). It's called a parametric curve.

The parametric curve is the path of the motion of the object, because each point (x, y) on it is a position (x, y) of the object in
the plane at time t, where x = f(t) and y = g(t). The direction of the motion is indicated by the arrow head. It of course
corresponds to increasing values of t. This direction is also treated as the direction of the curve.

Fig. 1.2 is obtained by adding the t-axis to Fig. 1.1 and changing a few labels. The t-axis is different from the x-axis and y-axis.
At time t = 0 the object is at the origin; at time t = t1 it's at position P1 = (x1, y1), at time t = tmax it's at position xmax on the # Position of object is function of time.

x-axis. Position of the object is a function of time.

In this section we take a closer look at parametric curves.

Definitions 1.1 – Parametric Curves

 The set of equations:   x = f(t), y = g(t),   where f and g are continuous functions on a common domain being some interval I of the real line R and t is an independent variable, is called parametric equations. The independent variable t is called the parameter. The set of all points (x, y), where x = f(t) and y = g(t), is called a parametric curve in the plane. Its direction corresponds to increasing values of t and is indicated by arrow head(s).

The parametric equations are an expressing of x and y in terms of the parameter. Since f and g are functions, for each value
of t in the common domain of f and g there corresponds exactly 1 value of x and exactly 1 value of y, thus exactly 1 point (x,
y) on the curve, where x = f(t) and y = g(t).

A Function Described By f And g

By the parametric equations x = f(t), y = g(t), for each value of t in the common domain I of f and g there corresponds
exactly 1 point (x, y) in the plane, where x = f(t) and y = g(t). See Fig. 1.3, where I = [a, b] with a < b. Let C be the curve
formed by such points. We can view the equations as describing a function say h (not f or g, and not a function or an equation
obtained by eliminating t) that maps each real number t in I to an ordered pair of real numbers (x, y) on C as follows: h(t) =
(x, y) = ( f(t), g(t)). It has domain I on the real line and range C in the plane. It's a function from (a subset of) R to (a subset
of) R2 (= R x R). Note that x = f(t), y = g(t), and y = F(x) are functions from R to R.

## Curve Is Graph Of Cartesian Equation Or A Part Of It

Suppose that from the parametric equations x = f(t), y = g(t) we get the Cartesian equation y = F(x) or G(x, y) = 0 by
eliminating t. The parametric curve of the parametric equations x = f(t), y = g(t) is the graph of the function y = F(x) or of
the equation G(x, y) = 0, because y = F(x) or G(x, y) = 0 is derived from the parametric equations. If there are restrictions
on x or y by the nature of the parametric equations as will be shown in some examples that follow, the curve may be just a
part of the graph of the Cartesian equation. It's called parametric because of the parametric equations. Refer to Fig. 1.3. As for
the axes, the t-axis is different from the x-axis and the y-axis of the xy-coordinate system of the plane of the curve. Remark
that the curve in Fig. 1.3 is the graph of an xy-equation G(x, y) = 0 that's not a function y = F(x). We'll see such curves in
some examples below.

If the Cartesian equation G(x, y) = 0 isn't recognized or if 1 such equation isn't obtained from the parametric equations, to
sketch the parametric curve in this section (another method is introduced in the next section) we'll have to rely on the “lo-tech”
table of values to get a number of points, and we'll also use properties of the curve if any, and then we'll join the points
together by a curve, as will be illustrated in an example below. ### Fig. 1.3

Curve C of parametric equations x = f(t), y = g(t) is graph of
Cartesian equation G(x, y) = 0. It's directed path of moving point
or object P whose coordinates are (x, y).

## Curve As Path Of Moving Object

Let P be the point (x, y) where x = f(t) and y = g(t), as in Fig. 1.3. At t = a, P is Pa. As t increases, P moves along the curve
C. At any t in [a, b], P is at a position (x, y) on C. At t = b, P is at Pb. The parametric equations x = f(t), y = g(t) specify
the coordinates (x, y) of the point P at parameter value t, and P represents an object moving in the plane. The parametric
curve C is the path of the moving object. Since f and g are continuous, C is continuous (has no breaks in it).

##### Direction Of Curve

The direction of the curve C is the direction of the motion of the object, and so it corresponds to increasing values of t. To
determine the direction of the curve let's take an example. Suppose t is in [0, 5]. We calculate the positions (x, y) = ( f(t),
g(t)) at t = 0, 1, 2, 3, 4, and 5. From this we get the direction of the motion of the object P(x, y) and thus the direction of the
curve, which we indicate on the curve by arrow head(s). Clearly we have to rely on the parametric equations to determine the
direction, which is lost in the Cartesian equation because it doesn't contain t.

## Parameter

The parameter t is sometimes referred to as time, because it often represents time. As illustrated in the examples that follow,
it can represent other quantities, and letters other than t can be used as parameter.

 2. Sketching Parametric Curves

## Example 2.1

a. Identify the parametric curve x = t + 1, y = t2 – 1, for all t in R.
b. Sketch it.
c. Label the points corresponding to t = –1, t = 0, and t = 1.
d. Determine its direction and indicate the direction on it.
e. Give an example quantity that the parameter t can represent.

#### y = x2 – 2x = x(x – 2), x-intercepts: x = 0 and 2, y-intercept: y = 0, y' = 2x – 2 = 2(x – 1), y' = 0 at x = 1, if x = 1 then y = –1, vertex: (1, –1), y'' = 2 > 0, concave up, curve is sketched in Fig. 2.1. ### Fig. 2.1

Parabola For Example 2.1.

#### e. The parameter t can represent time. EOS {2.1} Fig. 1.2.
{2.2} Fig. 1.3.

##### Example 2.2 Solution
x2 + y2 = 25 cos2 t + 25 sin2 t = 25(cos2 t + sin2 t) = 25(1) = 52,
the curve is the circle with centre at the origin and radius 5, sketched in Fig. 2.2. ### Fig. 2.2

Circle For Example 2.2. An interpretation of t is that it's the central angle associated with the point P(x, y).
EOS

Here the elimination of the parameter t is easier by using a trigonometric identity, sin2 x + cos2 x = 1, than by direct
substitution for t as in Example 2.1. The Cartesian equation x2 + y2 = 25 is recognized as that of a circle and isn't a function.
The parameter t is interpreted as an angle, since we're talking about its trigonometric functions. Remark that the circle isn't
the unit circle; its radius is 5, not 1. For example, the perpendicular projection x of P on the horizontal axis is x = ((segment
joining 0 to P) times (cos t)) = 5 cos t, not just cos t.

##### Example 2.3 Solution  ### Fig. 2.3

Partial Ellipse For Example 2.3.

EOS

In Example 2.2 the coefficients of cos and sin are equal, producing a circle. Here they're different, producing an ellipse, or a
part of it due to restrictions on the parameter. The restrictions on the parameter are specified with the parametric equations
and produce a partial ellipse.

##### Example 2.4

Sketch the curve having parametric representation x = sin t, y = 2 sin t, t in R. As t increases in R, describe the motion of an
object whose position in the plane at time t is given by these equations.

Solution  ### Fig. 2.4

“Curve” For Example 2.4.

EOS

##### Example 2.5 Solution  ### Fig. 2.5

Semi-Circle For Example 2.5.

EOS

The restrictions that may be placed on x or y by the nature of the parametric equations may not be contained or apparent in
the Cartesian equation derived from them by eliminating the parameter. We must examine this possibility carefully. In Example 2.3, the restrictions are on the parameter and are stated explicitly in the problem. The restrictions on x and y also
exist, but they're also contained in the Cartesian equation. Remark that, for that particular example, only a partial ellipse forms
the curve because of the restrictions on the parameter, not because of those on x and y.

In Example 2.5, the direction of the curve is clockwise, while in Example 2.2 it's counterclockwise. Clearly the direction of the
curve depends on the functions f and g.

Keep in mind that there are 2 kinds of restrictions: those on the parameter, which are specified with the parametric equations,
and those on x and y, which are implied by the nature of the parametric equations and aren’t contained or apparent in the
Cartesian equation.

##### Example 2.6

Sketch the curve defined by the parametric equations x = t3 – 3t, y = t2, t in [–2, 2]. Use its properties if any. Indicate its
direction.

Solution Symmetry. Now x is an odd function of t and y an even function of t. So at opposite values of t, x has opposite values and y
has the same value. Thus the curve is symmetric about the y-axis.  ### Fig. 2.6

Curve For Example 2.6.

EOS

The curve isn't recognized from its Cartesian equation, so we had to rely on the “lo-tech” table of values to get some points.
We also use the symmetry and self-intersection properties of the curve. A curve self-intersects at a point if it passes thru that
point 2 or more times from different directions, ie there are 3 or more different branches of it that are joined to that point,
which is passed thru for 2 or more different values of the parameter; so we look for self-intersection at points (x, y) that each
correspond to 2 or more different values of the parameter. (A circle with central-angle parameter in R passes thru every point
of it infinitely many times for different values of the parameter, but it doesn't self-intersect, because the repeated passing is
done from the same single direction; there are only 2 branches of the circle that are joined to each point.) Then we join the
points together by a curve. For clarity, points corresponding to fractional values of t in the table of values aren't labelled in
Fig. 2.6.

 3. Parametrization

Above, from parametric equations we derive corresponding Cartesian equations. Now we're going to perform the reverse.
From Cartesian equations we're going to derive corresponding parametric equations. We're also going to determine parametric
equations of some curves whose equations, Cartesian or otherwise, aren't known to us yet. To determine the parametric
equations of a curve is referred to as to parametrize it. The process of determining parametric equations of a curve and the
parametric equations themselves are each referred to as parametrization of the curve.

Since f and g in x = f(t) and y = g(t) are functions, where the parameter t is a particular quantity, for each value of t in the
common domain of f and g there corresponds exactly 1 value of x and exactly 1 value of y, thus exactly 1 point (x, y) on the
curve, where x = f(t) and y = g(t). If this rule is violated, then f or g or both don't exist, then the set of the 2 parametric
equations doesn't exist, then the curve can't be parametrized using the particular quantity t as the parameter.

##### Parametrization Of The Circle

In Example 2.2 we derive from the parametric equations x = 5 cos t, y = 5 sin t the Cartesian equation x2 + y2 = 25. Now
suppose we're given the circle x2 + y2 = 25 and we're asked to parametrize it. To do this we recall Example 2.2 and let x =
5 cos t and y = 5 sin t, then to verify we have x2 + y2 = 25 cos2 t + 25 sin2 t = 25(cos2 t + sin2 t) = 25(1) = 25. Or we let x =
5 cos t and calculate the t-expression for y. So a parametrization of the circle x2 + y2 = 25 is x = 5 cos t, y = 5 sin t, where t
is the central angle, as shown in Fig. 3.1. ### Fig. 3.1

A parametrization of circle x2 + y2 = 25 is x = 5 cos t, y = 5 sin t, where t is central
angle.

Now let's see if there are other parametrizations of the circle x2 + y2 = 25. The following are its valid parametrizations: The choice of a t-expression for x must of course be such that x2 + y2 = 25 and the selection for a t-interval must as a matter
of fact be such that x and y each assumes every value in [–5, 5] to get the full circle. The cosine and sine functions can
produce infinitely many parametrizations of such a circle: x = 5 cos h(t), y = 5 sin h(t), or x = 5 sin h(t), y = 5 cos h(t),
where h is a function of the form h(t) = tm or h(t) = mt and with a t-interval such that x and y have every value in [–5, 5]
(domain of h, which is the same as that of x and y because cosine and sine are defined everywhere on R, is such that the
ranges of x and y both are [–5, 5]).

In general, there are infinitely many parametrizations of the circle x2 + y2 = r2. One of them where t is the central angle is: You should memorize it as it's often utilized:

 A parametrization of the circle x2 + y2 = r2 using the central angle as parameter is: start and finish point: (r, 0), direction: counterclockwise. See Fig. 3.2. ### Fig. 3.2

Parametrization of circle x2 + y2 = r2 using central angle is x = r cos t, y = r sin t.

##### Parametrization Using A Specified Quantity As Parameter (Notice the t-interval. We must have the upper semi-circle only.) In this case the central angle is the quantity specified to be
used as parameter.

## Example 3.1

Parametrize the parabola y = x2 using its slope m at each point of it as parameter.

Solution
The slope of the parabola at each point (x, y) of it is m = y' = 2x. Then x = m/2 and y = x2 = (m/2)2 = m2/4. So the desired
parametrization is x = m/2, y = m2/4, m in R.
EOS

We express both x and y in terms of the slope m. For this purpose we determine an equation that relates x to m. To obtain
the entire parabola, the m-interval must be the entire set of real numbers, R. This example is simple enough that we don't
have to draw a picture for help if not asked to.

In general, to use a specified quantity as parameter we have to determine an equation that relates x or y to that quantity.

##### Example 3.2

Can you parametrize the curve y = x2 using as parameter the distance d from the general point (x, y) on the curve to the
origin (0, 0)? Why or why not?

Solution So no we can't, because each non-0 value of d corresponds to opposite values of x, thus to 2 different points (x, y) and (–x,
(–x)2) = (–x, x2) = (–x, y) on the curve.
EOS

The right-most expression gives the same value of d from opposite values of x. Each non-0 value of d corresponds to 2
different values of x, so to 2 different points on the curve, violating the rule that each value of the parameter corresponds to
exactly 1 point.

##### Example 3.3 – The Involute Of A Circle

A string is wound around a circle with equation x2 + y2 = r2. See Fig. 3.3. One end at the point A = (r, 0) is unwound in such a
way that the part of the string not lying on the circle is extended in a straight line. The curve I followed by this free end of the
string is called an involute of the circle. Let P be the position of the free end of the string at some subsequent time and let T
be the point where the string leaves the circle. Clearly PT is tangent to the circle at T. The path of P is the involute. Let O be
the origin (0, 0). Parametrize the involute employing the central angle TOA, denoted by s, as parameter. ### Fig. 3.3

Curve I is involute of circle.

## Solution ### Fig. 3.4

Parametrization Of Involute Of Circle Employing Central Angle As
Parameter.

Refer to Fig. 3.4. Let (x, y) be the coordinates of P, M the perpendicular projection of T on OA, and N the perpendicular
projection of P on TM. Then:

x = OM + NP,     y = MTNT,
OM = OT cos s = r cos s,
angle NTP = angle MTP = angle MOT = s, as arms of angle MTP are perpendicular to those of angle MOT,
PT = arc AT = rs, as s rad = (arc AT )/r,
NP = PT sin s = rs sin s,
x = r cos s + rs sin s;

MT = OT sin s = r sin s,
NT = PT cos s =  rs cos s,
y = r sin srs cos s.

The required parametrization is: ## EOS

Example 3.4 – The Cycloid

When a circle rolls along a straight line, the path traced by a point on it is called a cycloid. See Fig. 3.5. Suppose the circle has
radius r, lies above the x-axis, rolls along the x-axis starting from the origin O(0, 0) and rolling to the right. Let P be a point on
the circle and suppose it's originally at the origin. 2. Determine the x-intercepts, the x-coordinates corresponding to the maximum y-value, and the maximum y-value of the
cycloid by using:
a. Properties of the circle.
b. The parametric equations.
Indicate these values on the graph.

3. Show that (the horizontal component of the motion of) any point P on the circle never moves back as the circle rolls along
by using:
a. Geometry. Consider only the lower semi-circle, as it's only there that points seem to move back.
b. Calculus. ### Fig. 3.5

Curve C is cycloid.

## Solution

1. ### Fig. 3.6

Parametrizing The Cycloid In
Terms Of Angle Thru Which
The Circle Has Rolled.

Refer to Fig. 3.6. Take q to be positive as the circle rolls along to the right. Let (x, y) be the coordinates of P, M the centre of
the circle, N the point where the circle touches the x-axis, and Q the perpendicular projection of P on MN. Then:

x = ONPQ,     y = NM + MQ = r + MQ,

##  ## Fig. 3.7

As circle rolls along, any point on it never moves back.

## EOS

Contrary to what we may intuitively think, (the horizontal component of the motion of) any point P on the lower semi-circle
never moves back as the circle rolls along. An experiment to generate the cycloid is easy and cheap to set up and carry out.

##### Physical Properties Of The Inverted Cycloid ## Brachistochrone Property

The word “brachistochrone” comes from 2 Greek words that mean “shortest time”. Let Q be a given point in the 4th quadrant.
Suppose a small object slides without friction from the origin O(0, 0) along a curve to Q subject only to the downward force
mg due to gravity. What's the shape of the curve that causes the object to slide from O to Q in the least or shortest possible
time? Initially we might think that it should be the straight line, as the straight-line segment joining O and Q represents the
shortest distance between the 2 points. However the straight line isn't the answer. It can be shown that the answer is a portion ### Fig. 3.8

Physical Properties Of Inverted Cycloid.

of an arc of an inverted cycloid generated by a point P on a circle of radius r rolling on the under side of the x-axis along the
x-axis, with P starting at O, r being such that the cycloid contains Q, and the portion being between O and Q. This answer
appears to be reasonable: the curve should drop more steeply at first to allow the object to gain speed more quickly.

## Tautochrone Property

The word “tautochrone” comes from 2 Greek words that mean “same time”. Let an object be placed at a point other than the
low point on an arc of an inverted cycloid. It can be shown that the time required for it to slide to the low point is the same
for every initial point where it's placed. In other words, the time required for it to slide to the low point is independent of the
initial point where it's placed.

 4. Plane Curves

A plane curve is a continuous set of points in the plane that can be described by an xy-Cartesian-equation or a set of 2
parametric equations, as distinguished from plane regions. Clearly the parabola y = x2 and the circle x2 + y2 = 1 are plane
curves. They have Cartesian and parametric equations. Also clearly the involute of a circle and the cycloid are plane curves.
They have parametric equations. So we use the parametric equations to define plane curves. A plane curve is a curve that can
be described by a set of 2 parametric equations.

Definition 4.1 – Plane Curves

# Problems & Solutions

1.

a. Sketch the parametric curve x = t2 , y = t3, for all t in R.

b. Label the points corresponding to t = –1, t = 0, and t = 1.
c. Determine the direction of the curve and indicate the direction on it.
d. Give an example quantity that the parameter t can represent.

##### Solution

a. The curve is formed by the graphs of y = x3/2 and y = –x3/2. b. d.
The parameter t can represent time.

##### Note Without examining the t-interval which implies that y takes on negative values as well as positive ones we may not realize that
obtaining only the upper half of the curve is incorrect. Thus it's a good idea to always examine it and its implications.  ##### Solution    Solution its direction is clockwise.  4. Sketch the curve having parametric representation x = t2, y = t2 + 1, t in R. As t increases in R, describe the motion of an
object whose position in the plane at time t is given by these equations.

##### Solutions

y = t2 + 1 = x + 1.    ##### Solution   6. Can you parametrize the graph of y = x4 employing as parameter the following quantities at the general point (x, y) of the
graph? Why or why not?
a. The first derivative m.
b. The second derivative s.
c. The third derivative t.
d. The fourth derivative f.

##### Solution

a. So yes we can, because each value of t corresponds to exactly 1 point (x, y) on the graph.

d.
f = y(4) = 24.

So no we can't, because the single value of f corresponds to (infinitely) many points (x, y) on the graph.   ##### Solution

a.  b.

If a = 0 then the curve is the horizontal line y = r.

c.

If a = r then the curve is a cycloid.